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1/3x=5-x
We move all terms to the left:
1/3x-(5-x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/3x-(-1x+5)=0
We get rid of parentheses
1/3x+1x-5=0
We multiply all the terms by the denominator
1x*3x-5*3x+1=0
Wy multiply elements
3x^2-15x+1=0
a = 3; b = -15; c = +1;
Δ = b2-4ac
Δ = -152-4·3·1
Δ = 213
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{213}}{2*3}=\frac{15-\sqrt{213}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{213}}{2*3}=\frac{15+\sqrt{213}}{6} $
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