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1/3x=25+5x
We move all terms to the left:
1/3x-(25+5x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/3x-(5x+25)=0
We get rid of parentheses
1/3x-5x-25=0
We multiply all the terms by the denominator
-5x*3x-25*3x+1=0
Wy multiply elements
-15x^2-75x+1=0
a = -15; b = -75; c = +1;
Δ = b2-4ac
Δ = -752-4·(-15)·1
Δ = 5685
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-\sqrt{5685}}{2*-15}=\frac{75-\sqrt{5685}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+\sqrt{5685}}{2*-15}=\frac{75+\sqrt{5685}}{-30} $
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