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1/3x-x=4-3
We move all terms to the left:
1/3x-x-(4-3)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/3x-x-1=0
We add all the numbers together, and all the variables
-1x+1/3x-1=0
We multiply all the terms by the denominator
-1x*3x-1*3x+1=0
Wy multiply elements
-3x^2-3x+1=0
a = -3; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·(-3)·1
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{21}}{2*-3}=\frac{3-\sqrt{21}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{21}}{2*-3}=\frac{3+\sqrt{21}}{-6} $
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