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1/3x-5=1/6(-3+x)
We move all terms to the left:
1/3x-5-(1/6(-3+x))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6(-3+x))!=0We add all the numbers together, and all the variables
x∈R
1/3x-(1/6(x-3))-5=0
We calculate fractions
(6xx/(18x^2x+(-(1*3x)/(18x^2x-5=0
We can not solve this equation
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