1/3x-3=4+2x

Solution for 1/3x-3=4+2x equation:

1/3x-3=4+2x

We move all terms to the left:

1/3x-3-(4+2x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

1/3x-(2x+4)-3=0

We get rid of parentheses

1/3x-2x-4-3=0

We multiply all the terms by the denominator


-2x*3x-4*3x-3*3x+1=0

Wy multiply elements

-6x^2-12x-9x+1=0

We add all the numbers together, and all the variables

-6x^2-21x+1=0

a = -6; b = -21; c = +1;
Δ = b2-4ac
Δ = -212-4·(-6)·1
Δ = 465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{465}}{2*-6}=\frac{21-\sqrt{465}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{465}}{2*-6}=\frac{21+\sqrt{465}}{-12}
$