1/3x-3/8x=2

Solution for 1/3x-3/8x=2 equation:

1/3x-3/8x=2

We move all terms to the left:

1/3x-3/8x-(2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R


We calculate fractions


8x/24x^2+(-9x)/24x^2-2=0

We multiply all the terms by the denominator


8x+(-9x)-2*24x^2=0

Wy multiply elements

-48x^2+8x+(-9x)=0

We get rid of parentheses

-48x^2+8x-9x=0

We add all the numbers together, and all the variables

-48x^2-1x=0

a = -48; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-48)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-48}=\frac{0}{-96}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-48}=\frac{2}{-96}
=-1/48
$