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1/3x-2/3=-9-2/5x
We move all terms to the left:
1/3x-2/3-(-9-2/5x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/3x-(-2/5x-9)-2/3=0
We get rid of parentheses
1/3x+2/5x+9-2/3=0
We calculate fractions
5x/135x^2+54x/135x^2+(-10x)/135x^2+9=0
We multiply all the terms by the denominator
5x+54x+(-10x)+9*135x^2=0
We add all the numbers together, and all the variables
59x+(-10x)+9*135x^2=0
Wy multiply elements
1215x^2+59x+(-10x)=0
We get rid of parentheses
1215x^2+59x-10x=0
We add all the numbers together, and all the variables
1215x^2+49x=0
a = 1215; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·1215·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*1215}=\frac{-98}{2430} =-49/1215 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*1215}=\frac{0}{2430} =0 $
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