1/3x-10=-3x+10

Solution for 1/3x-10=-3x+10 equation:

1/3x-10=-3x+10

We move all terms to the left:

1/3x-10-(-3x+10)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

1/3x+3x-10-10=0

We multiply all the terms by the denominator


3x*3x-10*3x-10*3x+1=0

Wy multiply elements

9x^2-30x-30x+1=0

We add all the numbers together, and all the variables

9x^2-60x+1=0

a = 9; b = -60; c = +1;
Δ = b2-4ac
Δ = -602-4·9·1
Δ = 3564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3564}=\sqrt{324*11}=\sqrt{324}*\sqrt{11}=18\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-18\sqrt{11}}{2*9}=\frac{60-18\sqrt{11}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+18\sqrt{11}}{2*9}=\frac{60+18\sqrt{11}}{18}
$