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1/3x-1/x=4
We move all terms to the left:
1/3x-1/x-(4)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x!=0We calculate fractions
x∈R
x/3x^2+(-3x)/3x^2-4=0
We multiply all the terms by the denominator
x+(-3x)-4*3x^2=0
Wy multiply elements
-12x^2+x+(-3x)=0
We get rid of parentheses
-12x^2+x-3x=0
We add all the numbers together, and all the variables
-12x^2-2x=0
a = -12; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-12)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-12}=\frac{0}{-24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-12}=\frac{4}{-24} =-1/6 $
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