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1/3x-1/6x=26
We move all terms to the left:
1/3x-1/6x-(26)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x!=0We calculate fractions
x!=0/6
x!=0
x∈R
6x/18x^2+(-3x)/18x^2-26=0
We multiply all the terms by the denominator
6x+(-3x)-26*18x^2=0
Wy multiply elements
-468x^2+6x+(-3x)=0
We get rid of parentheses
-468x^2+6x-3x=0
We add all the numbers together, and all the variables
-468x^2+3x=0
a = -468; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-468)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-468}=\frac{-6}{-936} =1/156 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-468}=\frac{0}{-936} =0 $
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