1/3x-1/4x=1/2+0

Solution for 1/3x-1/4x=1/2+0 equation:

1/3x-1/4x=1/2+0

We move all terms to the left:

1/3x-1/4x-(1/2+0)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

1/3x-1/4x-(+1/2)=0

We get rid of parentheses

1/3x-1/4x-1/2=0

We calculate fractions


(-48x^2)/48x^2+16x/48x^2+(-12x)/48x^2=0

We multiply all the terms by the denominator


(-48x^2)+16x+(-12x)=0

We get rid of parentheses

-48x^2+16x-12x=0

We add all the numbers together, and all the variables

-48x^2+4x=0

a = -48; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-48)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-48}=\frac{-8}{-96}
=1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-48}=\frac{0}{-96}
=0
$