1/3x+8=-2x=-18

Solution for 1/3x+8=-2x=-18 equation:

1/3x+8=-2x=-18

We move all terms to the left:

1/3x+8-(-2x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

1/3x+2x+8=0

We multiply all the terms by the denominator


2x*3x+8*3x+1=0

Wy multiply elements

6x^2+24x+1=0

a = 6; b = 24; c = +1;
Δ = b2-4ac
Δ = 242-4·6·1
Δ = 552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{552}=\sqrt{4*138}=\sqrt{4}*\sqrt{138}=2\sqrt{138}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-2\sqrt{138}}{2*6}=\frac{-24-2\sqrt{138}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+2\sqrt{138}}{2*6}=\frac{-24+2\sqrt{138}}{12}
$