1/3x+7/2x=5/6-2/x

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Solution for 1/3x+7/2x=5/6-2/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/3)*x+(7/2)*x = 5/6-(2/x) // - 5/6-(2/x)

(1/3)*x+(7/2)*x+2/x-(5/6) = 0

(1/3)*x+(7/2)*x+2/x-5/6 = 0

23/6*x^1+2*x^-1-5/6*x^0 = 0

(23/6*x^2-5/6*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(23/6*x^2-5/6*x^1+2*x^0) = 0

x^1

(23/6)*x^2+(-5/6)*x+2 = 0

(23/6)*x^2+(-5/6)*x+2 = 0

DELTA = (-5/6)^2-(2*4*(23/6))

DELTA = -1079/36

DELTA < 0

x in { } 

x belongs to the empty set

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