1/3x+4=x-5

Solution for 1/3x+4=x-5 equation:

1/3x+4=x-5

We move all terms to the left:

1/3x+4-(x-5)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

1/3x-x+5+4=0

We multiply all the terms by the denominator


-x*3x+5*3x+4*3x+1=0

Wy multiply elements

-3x^2+15x+12x+1=0

We add all the numbers together, and all the variables

-3x^2+27x+1=0

a = -3; b = 27; c = +1;
Δ = b2-4ac
Δ = 272-4·(-3)·1
Δ = 741
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{741}}{2*-3}=\frac{-27-\sqrt{741}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{741}}{2*-3}=\frac{-27+\sqrt{741}}{-6}
$