1/3x+3=26+6/18x+23

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Solution for 1/3x+3=26+6/18x+23 equation: 



1/3x+3=26+6/18x+23

We move all terms to the left:

1/3x+3-(26+6/18x+23)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 18x+23)!=0

x∈R



We add all the numbers together, and all the variables

1/3x-(6/18x+49)+3=0

We get rid of parentheses

1/3x-6/18x-49+3=0

We calculate fractions


18x/54x^2+(-18x)/54x^2-49+3=0

We add all the numbers together, and all the variables

18x/54x^2+(-18x)/54x^2-46=0

We multiply all the terms by the denominator


18x+(-18x)-46*54x^2=0

Wy multiply elements

-2484x^2+18x+(-18x)=0

We get rid of parentheses

-2484x^2+18x-18x=0

We add all the numbers together, and all the variables

-2484x^2=0

a = -2484; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2484)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4968}=0$

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