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1/3x+2/3=1/4x+3
We move all terms to the left:
1/3x+2/3-(1/4x+3)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x+3)!=0We get rid of parentheses
x∈R
1/3x-1/4x-3+2/3=0
We calculate fractions
4x/108x^2+(-27x)/108x^2+8x/108x^2-3=0
We multiply all the terms by the denominator
4x+(-27x)+8x-3*108x^2=0
We add all the numbers together, and all the variables
12x+(-27x)-3*108x^2=0
Wy multiply elements
-324x^2+12x+(-27x)=0
We get rid of parentheses
-324x^2+12x-27x=0
We add all the numbers together, and all the variables
-324x^2-15x=0
a = -324; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·(-324)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*-324}=\frac{0}{-648} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*-324}=\frac{30}{-648} =-5/108 $
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