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1/3x+1/4x=7/24
We move all terms to the left:
1/3x+1/4x-(7/24)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
1/3x+1/4x-(+7/24)=0
We get rid of parentheses
1/3x+1/4x-7/24=0
We calculate fractions
(-336x^2)/576x^2+192x/576x^2+144x/576x^2=0
We multiply all the terms by the denominator
(-336x^2)+192x+144x=0
We add all the numbers together, and all the variables
(-336x^2)+336x=0
We get rid of parentheses
-336x^2+336x=0
a = -336; b = 336; c = 0;
Δ = b2-4ac
Δ = 3362-4·(-336)·0
Δ = 112896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{112896}=336$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(336)-336}{2*-336}=\frac{-672}{-672} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(336)+336}{2*-336}=\frac{0}{-672} =0 $
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