1/3x(6x-12)=1/4(16x-8)

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Solution for 1/3x(6x-12)=1/4(16x-8) equation: 



1/3x(6x-12)=1/4(16x-8)

We move all terms to the left:

1/3x(6x-12)-(1/4(16x-8))=0



Domain of the equation: 3x(6x-12)!=0

x∈R





Domain of the equation: 4(16x-8))!=0

x∈R



We calculate fractions


(4x1/(3x(6x-12)*4(16x-8)))+(-3x6/(3x(6x-12)*4(16x-8)))=0



We calculate terms in parentheses: +(4x1/(3x(6x-12)*4(16x-8))), so:

4x1/(3x(6x-12)*4(16x-8))

We multiply all the terms by the denominator


4x1

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-3x6/(3x(6x-12)*4(16x-8))), so:

-3x6/(3x(6x-12)*4(16x-8))

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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