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1/3x(5x-4)+5/6(7-5x)=7/4(3x-5)
We move all terms to the left:
1/3x(5x-4)+5/6(7-5x)-(7/4(3x-5))=0
Domain of the equation: 3x(5x-4)!=0
x∈R
Domain of the equation: 6(7-5x)!=0
x∈R
Domain of the equation: 4(3x-5))!=0We add all the numbers together, and all the variables
x∈R
1/3x(5x-4)+5/6(-5x+7)-(7/4(3x-5))=0
We calculate fractions
We do not support expression: x^2(
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