1/3x(4-8x+9)=-9(4x-6)

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Solution for 1/3x(4-8x+9)=-9(4x-6) equation: 



1/3x(4-8x+9)=-9(4x-6)

We move all terms to the left:

1/3x(4-8x+9)-(-9(4x-6))=0



Domain of the equation: 3x(4-8x+9)!=0

x∈R



We add all the numbers together, and all the variables

1/3x(-8x+13)-(-9(4x-6))=0

We multiply all the terms by the denominator


-((-9(4x-6)))*3x(-8x+13)+1=0



We calculate terms in parentheses: -((-9(4x-6)))*3x(-8x+13), so:

(-9(4x-6)))*3x(-8x+13

We add all the numbers together, and all the variables

-8x+(-9(4x-6)))*3x(+13

Back to the equation:

-(-8x+(-9(4x-6)))*3x(+13)



We add all the numbers together, and all the variables

-(-8x+(-9(4x-6)))*3x13+1=0

We move all terms containing x to the left, all other terms to the right

-(-8x+(-9(4x-6)))*3x13=-1

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