1/3x(-13)=4/3x(-23)

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Solution for 1/3x(-13)=4/3x(-23) equation: 



1/3x(-13)=4/3x(-23)

We move all terms to the left:

1/3x(-13)-(4/3x(-23))=0



Domain of the equation: 3x(-13)!=0

x∈R





Domain of the equation: 3x(-23))!=0

x∈R



We calculate fractions


(3x(-)/(3x(-13)*3x(-23)))+(-12x0/(3x(-13)*3x(-23)))=0



We calculate terms in parentheses: +(3x(-)/(3x(-13)*3x(-23))), so:

3x(-)/(3x(-13)*3x(-23))

We add all the numbers together, and all the variables

3x0/(3x(-13)*3x(-23))

We multiply all the terms by the denominator


3x0

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-12x0/(3x(-13)*3x(-23))), so:

-12x0/(3x(-13)*3x(-23))

We multiply all the terms by the denominator


-12x0

We add all the numbers together, and all the variables

-12x

Back to the equation:

+(-12x)



We get rid of parentheses

3x-12x=0

We add all the numbers together, and all the variables

-9x=0

x=0/-9

x=0

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