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1/3n+2=2/3(n+3)
We move all terms to the left:
1/3n+2-(2/3(n+3))=0
Domain of the equation: 3n!=0
n!=0/3
n!=0
n∈R
Domain of the equation: 3(n+3))!=0We calculate fractions
n∈R
(3nn/(9n^2n+(-(2*3n)/(9n^2n+2=0
We can not solve this equation
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