1/3m+1/4m=7/24

Solution for 1/3m+1/4m=7/24 equation:

1/3m+1/4m=7/24

We move all terms to the left:

1/3m+1/4m-(7/24)=0


Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R



Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R


We add all the numbers together, and all the variables

1/3m+1/4m-(+7/24)=0

We get rid of parentheses

1/3m+1/4m-7/24=0

We calculate fractions


(-336m^2)/576m^2+192m/576m^2+144m/576m^2=0

We multiply all the terms by the denominator


(-336m^2)+192m+144m=0

We add all the numbers together, and all the variables

(-336m^2)+336m=0

We get rid of parentheses

-336m^2+336m=0

a = -336; b = 336; c = 0;
Δ = b2-4ac
Δ = 3362-4·(-336)·0
Δ = 112896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{112896}=336$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(336)-336}{2*-336}=\frac{-672}{-672}
=1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(336)+336}{2*-336}=\frac{0}{-672}
=0
$