1/3ln(4x-3)=2

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Solution for 1/3ln(4x-3)=2 equation: 


D( x )

4*x-3 <= 0

4*x-3 <= 0

4*x-3 <= 0

4*x-3 <= 0 // + 3

4*x <= 3 // : 4

x <= 3/4

x in (3/4:+oo)

(1/3)*ln(4*x-3) = 2 // - 2

(1/3)*ln(4*x-3)-2 = 0

1/3*ln(4*x-3)-2 = 0 // + 2

1/3*ln(4*x-3) = 2 // : 1/3

ln(4*x-3) = 2/1/3

ln(4*x-3) = 6

ln(4*x-3) = ln(e^6)

4*x-3 = e^6

4*x-e^6-3 = 0 // + e^6+3

4*x = e^6+3 // : 4

x = (e^6+3)/4

x = (e^6+3)/4

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