1/3k-7=1/3(k-12)

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Solution for 1/3k-7=1/3(k-12) equation:



1/3k-7=1/3(k-12)
We move all terms to the left:
1/3k-7-(1/3(k-12))=0
Domain of the equation: 3k!=0
k!=0/3
k!=0
k∈R
Domain of the equation: 3(k-12))!=0
k∈R
We calculate fractions
(3kk/(9k^2k+(-(1*3k)/(9k^2k-7=0
We can not solve this equation

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