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1/3h=10
We move all terms to the left:
1/3h-(10)=0
Domain of the equation: 3h!=0We multiply all the terms by the denominator
h!=0/3
h!=0
h∈R
-10*3h+1=0
Wy multiply elements
-30h+1=0
We move all terms containing h to the left, all other terms to the right
-30h=-1
h=-1/-30
h=1/30
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