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1/3h+1/4(h+12)=24
We move all terms to the left:
1/3h+1/4(h+12)-(24)=0
Domain of the equation: 3h!=0
h!=0/3
h!=0
h∈R
Domain of the equation: 4(h+12)!=0We calculate fractions
h∈R
(4hh/(12h^2h+3h/(12h^2h-24=0
We can not solve this equation
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