1/3c+6=12

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Solution for 1/3c+6=12 equation: 



1/3c+6=12

We move all terms to the left:

1/3c+6-(12)=0



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



We add all the numbers together, and all the variables

1/3c-6=0

We multiply all the terms by the denominator


-6*3c+1=0

Wy multiply elements

-18c+1=0

We move all terms containing c to the left, all other terms to the right

-18c=-1

c=-1/-18

c=1/18

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