1/3c+1/4c=2-9

Solution for 1/3c+1/4c=2-9 equation:

1/3c+1/4c=2-9

We move all terms to the left:

1/3c+1/4c-(2-9)=0


Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R


We add all the numbers together, and all the variables

1/3c+1/4c-(-7)=0

We add all the numbers together, and all the variables

1/3c+1/4c+7=0

We calculate fractions


4c/12c^2+3c/12c^2+7=0

We multiply all the terms by the denominator


4c+3c+7*12c^2=0

We add all the numbers together, and all the variables

7c+7*12c^2=0

Wy multiply elements

84c^2+7c=0

a = 84; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·84·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*84}=\frac{-14}{168}
=-1/12
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*84}=\frac{0}{168}
=0
$