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1/3a+2=1/3(4a+1)
We move all terms to the left:
1/3a+2-(1/3(4a+1))=0
Domain of the equation: 3a!=0
a!=0/3
a!=0
a∈R
Domain of the equation: 3(4a+1))!=0We calculate fractions
a∈R
(3a4/(9a^24+(-(1*3a)/(9a^24+2=0
We do not support eapression: a^24
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