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1/3a+1/6a=-1
We move all terms to the left:
1/3a+1/6a-(-1)=0
Domain of the equation: 3a!=0
a!=0/3
a!=0
a∈R
Domain of the equation: 6a!=0We add all the numbers together, and all the variables
a!=0/6
a!=0
a∈R
1/3a+1/6a+1=0
We calculate fractions
6a/18a^2+3a/18a^2+1=0
We multiply all the terms by the denominator
6a+3a+1*18a^2=0
We add all the numbers together, and all the variables
9a+1*18a^2=0
Wy multiply elements
18a^2+9a=0
a = 18; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·18·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*18}=\frac{-18}{36} =-1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*18}=\frac{0}{36} =0 $
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