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1/32x=5x-6
We move all terms to the left:
1/32x-(5x-6)=0
Domain of the equation: 32x!=0We get rid of parentheses
x!=0/32
x!=0
x∈R
1/32x-5x+6=0
We multiply all the terms by the denominator
-5x*32x+6*32x+1=0
Wy multiply elements
-160x^2+192x+1=0
a = -160; b = 192; c = +1;
Δ = b2-4ac
Δ = 1922-4·(-160)·1
Δ = 37504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{37504}=\sqrt{64*586}=\sqrt{64}*\sqrt{586}=8\sqrt{586}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(192)-8\sqrt{586}}{2*-160}=\frac{-192-8\sqrt{586}}{-320} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(192)+8\sqrt{586}}{2*-160}=\frac{-192+8\sqrt{586}}{-320} $
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