1/3+h-4(2/3h-3)=2/3h-6

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Solution for 1/3+h-4(2/3h-3)=2/3h-6 equation: 



1/3+h-4(2/3h-3)=2/3h-6

We move all terms to the left:

1/3+h-4(2/3h-3)-(2/3h-6)=0



Domain of the equation: 3h-3)!=0

h∈R





Domain of the equation: 3h-6)!=0

h∈R



We multiply parentheses

h-8h-(2/3h-6)+12+1/3=0

We get rid of parentheses

h-8h-2/3h+6+12+1/3=0

We calculate fractions


h-8h+6+12=0

We add all the numbers together, and all the variables

-7h+18=0

We move all terms containing h to the left, all other terms to the right

-7h=-18

h=-18/-7

h=2+4/7

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