1/3(y-1)+6=7/9(3y-3)

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Solution for 1/3(y-1)+6=7/9(3y-3) equation: 



1/3(y-1)+6=7/9(3y-3)

We move all terms to the left:

1/3(y-1)+6-(7/9(3y-3))=0



Domain of the equation: 3(y-1)!=0

y∈R





Domain of the equation: 9(3y-3))!=0

y∈R



We calculate fractions


(9y3/(3(y-1)*9(3y-3)))+(-21yy/(3(y-1)*9(3y-3)))+6=0



We calculate terms in parentheses: +(9y3/(3(y-1)*9(3y-3))), so:

9y3/(3(y-1)*9(3y-3))

We multiply all the terms by the denominator


9y3

We add all the numbers together, and all the variables

9y^3

We do not support eypression: y^3

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