1/3(y+1)=2/3y

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Solution for 1/3(y+1)=2/3y equation: 


y in (-oo:+oo)

(1/3)*(y+1) = (2/3)*y // - (2/3)*y

(1/3)*(y+1)-((2/3)*y) = 0

(1/3)*(y+1)+(-2/3)*y = 0

1/3*(y+1)+(-2*y)/3 = 0

(1/3*3*(y+1))/3+(-2*y)/3 = 0

1/3*3*(y+1)-2*y = 0

1-y = 0

(1-y)/3 = 0

(1-y)/3 = 0 // * 3

1-y = 0

1-y = 0 // - 1

-y = -1 // * -1

y = 1

y = 1

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