1/3(y+1)=1/6(3y-5)

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Solution for 1/3(y+1)=1/6(3y-5) equation:



1/3(y+1)=1/6(3y-5)
We move all terms to the left:
1/3(y+1)-(1/6(3y-5))=0
Domain of the equation: 3(y+1)!=0
y∈R
Domain of the equation: 6(3y-5))!=0
y∈R
We calculate fractions
(6y3/(3(y+1)*6(3y-5)))+(-3yy/(3(y+1)*6(3y-5)))=0
We calculate terms in parentheses: +(6y3/(3(y+1)*6(3y-5))), so:
6y3/(3(y+1)*6(3y-5))
We multiply all the terms by the denominator
6y3
We add all the numbers together, and all the variables
6y^3
We do not support eypression: y^3

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