1/3(x-9)=1/9(x+27)

Solution for 1/3(x-9)=1/9(x+27) equation:

1/3(x-9)=1/9(x+27)

We move all terms to the left:

1/3(x-9)-(1/9(x+27))=0


Domain of the equation: 3(x-9)!=0

x∈R



Domain of the equation: 9(x+27))!=0

x∈R


We calculate fractions


(9xx/(3(x-9)*9(x+27)))+(-3xx/(3(x-9)*9(x+27)))=0


We calculate terms in parentheses: +(9xx/(3(x-9)*9(x+27))), so:

9xx/(3(x-9)*9(x+27))

We multiply all the terms by the denominator


9xx

Back to the equation:

+(9xx)



We calculate terms in parentheses: +(-3xx/(3(x-9)*9(x+27))), so:

-3xx/(3(x-9)*9(x+27))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

9xx-3xx=0