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1/3(x-4)-5=7
We move all terms to the left:
1/3(x-4)-5-(7)=0
Domain of the equation: 3(x-4)!=0We add all the numbers together, and all the variables
x∈R
1/3(x-4)-12=0
We multiply all the terms by the denominator
-12*3(x-4)+1=0
Wy multiply elements
-36x(x+1=0
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