1/3(x-4)+1/12(2x-5)=1/4x

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Solution for 1/3(x-4)+1/12(2x-5)=1/4x equation: 



1/3(x-4)+1/12(2x-5)=1/4x

We move all terms to the left:

1/3(x-4)+1/12(2x-5)-(1/4x)=0



Domain of the equation: 3(x-4)!=0

x∈R





Domain of the equation: 12(2x-5)!=0

x∈R





Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/3(x-4)+1/12(2x-5)-(+1/4x)=0

We get rid of parentheses

1/3(x-4)+1/12(2x-5)-1/4x=0

We calculate fractions


(48x^22/(3(x-4)*12(2x-5)*4x)+(12x^2x/(3(x-4)*12(2x-5)*4x)+(-36x^2x/(3(x-4)*12(2x-5)*4x)=0



We calculate terms in parentheses: +(48x^22/(3(x-4)*12(2x-5)*4x)+(12x^2x/(3(x-4)*12(2x-5)*4x)+(-36x^2x/(3(x-4)*12(2x-5)*4x), so:

48x^22/(3(x-4)*12(2x-5)*4x)+(12x^2x/(3(x-4)*12(2x-5)*4x)+(-36x^2x/(3(x-4)*12(2x-5)*4x

We do not support expression: x^22

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