1/3(x-2)=2/5(3x+3)

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Solution for 1/3(x-2)=2/5(3x+3) equation: 



1/3(x-2)=2/5(3x+3)

We move all terms to the left:

1/3(x-2)-(2/5(3x+3))=0



Domain of the equation: 3(x-2)!=0

x∈R





Domain of the equation: 5(3x+3))!=0

x∈R



We calculate fractions


(5x3/(3(x-2)*5(3x+3)))+(-6xx/(3(x-2)*5(3x+3)))=0



We calculate terms in parentheses: +(5x3/(3(x-2)*5(3x+3))), so:

5x3/(3(x-2)*5(3x+3))

We multiply all the terms by the denominator


5x3

We add all the numbers together, and all the variables

5x^3

We do not support expression: x^3

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