1/3(x+3)=1/6(x+9)

Solution for 1/3(x+3)=1/6(x+9) equation:

1/3(x+3)=1/6(x+9)

We move all terms to the left:

1/3(x+3)-(1/6(x+9))=0


Domain of the equation: 3(x+3)!=0

x∈R



Domain of the equation: 6(x+9))!=0

x∈R


We calculate fractions


(6xx/(3(x+3)*6(x+9)))+(-3xx/(3(x+3)*6(x+9)))=0


We calculate terms in parentheses: +(6xx/(3(x+3)*6(x+9))), so:

6xx/(3(x+3)*6(x+9))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)



We calculate terms in parentheses: +(-3xx/(3(x+3)*6(x+9))), so:

-3xx/(3(x+3)*6(x+9))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

6xx-3xx=0