1/3(x+3)-1/6=1/6(2x+5)

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Solution for 1/3(x+3)-1/6=1/6(2x+5) equation: 



1/3(x+3)-1/6=1/6(2x+5)

We move all terms to the left:

1/3(x+3)-1/6-(1/6(2x+5))=0



Domain of the equation: 3(x+3)!=0

x∈R





Domain of the equation: 6(2x+5))!=0

x∈R



We calculate fractions


(36x2/(3(x+3)*6(2x+5))*6)+(-3xx/(3(x+3)*6(2x+5))*6)+(-3xx/(3(x+3)*6(2x+5))*6)=0



We calculate terms in parentheses: +(36x2/(3(x+3)*6(2x+5))*6), so:

36x2/(3(x+3)*6(2x+5))*6

We multiply all the terms by the denominator


36x2

We add all the numbers together, and all the variables

36x^2

Back to the equation:

+(36x^2)





We calculate terms in parentheses: +(-3xx/(3(x+3)*6(2x+5))*6), so:

-3xx/(3(x+3)*6(2x+5))*6

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)





We calculate terms in parentheses: +(-3xx/(3(x+3)*6(2x+5))*6), so:

-3xx/(3(x+3)*6(2x+5))*6

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)



We get rid of parentheses

36x^2-3xx-3xx=0

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