1/3(x+3)+5/6(x-4)=x+2

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Solution for 1/3(x+3)+5/6(x-4)=x+2 equation: 



1/3(x+3)+5/6(x-4)=x+2

We move all terms to the left:

1/3(x+3)+5/6(x-4)-(x+2)=0



Domain of the equation: 3(x+3)!=0

x∈R





Domain of the equation: 6(x-4)!=0

x∈R



We get rid of parentheses

1/3(x+3)+5/6(x-4)-x-2=0

We calculate fractions


-x+(6xx/(3(x+3)*6(x-4))+(15xx/(3(x+3)*6(x-4))-2=0

We can not solve this equation

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