1/3(x+3)+1/12(x-12)=x+7

Simple and best practice solution for 1/3(x+3)+1/12(x-12)=x+7 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 1/3(x+3)+1/12(x-12)=x+7 equation:


x in (-oo:+oo)

(1/3)*(x+3)+(1/12)*(x-12) = x+7 // - x+7

(1/3)*(x+3)+(1/12)*(x-12)-x-7 = 0

1/3*(x+3)+1/12*(x-12)-x-7 = 0

1/3*(x+3)+1/12*(x-12)-x-7 = 0

5/12*x-x-7 = 0

-7/12*x-7 = 0

-7/12*x-7 = 0

-7/12*x-7 = 0 // + 7

-7/12*x = 7 // : -7/12

x = 7/(-7/12)

x = -12

x = -12

See similar equations:

| 2-x=20-4x | | x^2+y^2=sqrt(43.2) | | 5x-y+y= | | 2x+3=11x | | 4x^2-13x+8=-4x+6 | | 6(z+3)-4z=8 | | y=x^2+8x-4 | | 3x-5(x-3)=9 | | 18x-9x^2=0 | | 20x+100=30x+80 | | -13-ex=7-7x | | (7y+7)-(5+6y)=12 | | 4x+15=3x+19 | | 2(7x+13)=54 | | -7x-(3x+3)=-6x+3 | | 1-x=-2x-11 | | 2(5y-7)=-4 | | x-6=2x-12 | | 2j(7j^2k^2+jk^2+5k)-9k(-2j^2k^2+2k^2+3j)= | | S+3=22 | | 3(6y-6)=18 | | 29=x^2+4 | | -5x-12/-8=9 | | 33000+0.013s=101900 | | (x-5)(x^2+7x-5)= | | p=-x^2+105x+1050 | | 5x+166=13x-10 | | x^2-1/5x | | 25-g=36 | | (x/-7)-2=10 | | 13-8x=168-43x | | -7x+4(x+15)=84 |

Equations solver categories