1/3(x+2)=7x-15(1-x)-6

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Solution for 1/3(x+2)=7x-15(1-x)-6 equation: 


x in (-oo:+oo)

(1/3)*(x+2) = 7*x-(15*(1-x))-6 // - 7*x-(15*(1-x))-6

(1/3)*(x+2)+15*(1-x)-(7*x)+6 = 0

(1/3)*(x+2)+15*(1-x)-7*x+6 = 0

1/3*(x+2)+15*(1-x)-7*x+6 = 0

1/3*(x+2)+15*(1-x)-7*x+6 = 0

6-44/3*x-7*x+47/3 = 0

6-65/3*x+47/3 = 0

65/3-65/3*x = 0

65/3-65/3*x = 0

65/3-65/3*x = 0 // - 65/3

-65/3*x = -65/3 // : -65/3

x = -65/3/(-65/3)

x = 1

x = 1

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