1/3(x+2)=2/3(x+4)

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Solution for 1/3(x+2)=2/3(x+4) equation: 



1/3(x+2)=2/3(x+4)

We move all terms to the left:

1/3(x+2)-(2/3(x+4))=0



Domain of the equation: 3(x+2)!=0

x∈R





Domain of the equation: 3(x+4))!=0

x∈R



We calculate fractions


(3xx/(3(x+2)*3(x+4)))+(-6xx/(3(x+2)*3(x+4)))=0



We calculate terms in parentheses: +(3xx/(3(x+2)*3(x+4))), so:

3xx/(3(x+2)*3(x+4))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-6xx/(3(x+2)*3(x+4))), so:

-6xx/(3(x+2)*3(x+4))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)



We get rid of parentheses

3xx-6xx=0

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