1/3(x+2)+3/2(x+4)=1/6x+5

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Solution for 1/3(x+2)+3/2(x+4)=1/6x+5 equation: 


x in (-oo:+oo)

(1/3)*(x+2)+(3/2)*(x+4) = (1/6)*x+5 // - (1/6)*x+5

(1/3)*(x+2)+(3/2)*(x+4)-((1/6)*x)-5 = 0

(1/3)*(x+2)+(3/2)*(x+4)+(-1/6)*x-5 = 0

1/3*(x+2)+3/2*(x+4)-x/6-5 = 0

(1/3*6*(x+2))/6+(3/2*6*(x+4))/6-x/6+(-5*6)/6 = 0

1/3*6*(x+2)+3/2*6*(x+4)-x-5*6 = 0

11*x-x-30+40 = 0

10*x-30+40 = 0

10*x+10 = 0

(10*x+10)/6 = 0

(10*x+10)/6 = 0 // * 6

10*x+10 = 0

10*x+10 = 0 // - 10

10*x = -10 // : 10

x = -10/10

x = -1

x = -1

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