1/3(x+1)=2/5x+7/9

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Solution for 1/3(x+1)=2/5x+7/9 equation: 


x in (-oo:+oo)

(1/3)*(x+1) = (2/5)*x+7/9 // - (2/5)*x+7/9

(1/3)*(x+1)-((2/5)*x)-(7/9) = 0

(1/3)*(x+1)+(-2/5)*x-7/9 = 0

1/3*(x+1)+(-2*x)/5-7/9 = 0

(1/3*5*9*(x+1))/(5*9)+(-2*9*x)/(5*9)+(-7*5)/(5*9) = 0

1/3*5*9*(x+1)-2*9*x-7*5 = 0

15-3*x-35 = 0

-3*x-20 = 0

(-3*x-20)/(5*9) = 0

(-3*x-20)/(5*9) = 0 // * 5*9

-3*x-20 = 0

-3*x-20 = 0 // + 20

-3*x = 20 // : -3

x = 20/(-3)

x = -20/3

x = -20/3

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