1/3(x+1)-1/2(x+1)=5/6(x+2)

Solution for 1/3(x+1)-1/2(x+1)=5/6(x+2) equation:

1/3(x+1)-1/2(x+1)=5/6(x+2)

We move all terms to the left:

1/3(x+1)-1/2(x+1)-(5/6(x+2))=0


Domain of the equation: 3(x+1)!=0

x∈R



Domain of the equation: 2(x+1)!=0

x∈R



Domain of the equation: 6(x+2))!=0

x∈R


We calculate fractions


(-18x^2x/(3(x+1)*2(x+1)*6(x+2)))+(-30x^2x/(3(x+1)*2(x+1)*6(x+2)))+(12x^2x/(3(x+1)*2(x+1)*6(x+2)))=0


We calculate terms in parentheses: +(-18x^2x/(3(x+1)*2(x+1)*6(x+2))), so:

-18x^2x/(3(x+1)*2(x+1)*6(x+2))

We multiply all the terms by the denominator


-18x^2x

Back to the equation:

+(-18x^2x)



We calculate terms in parentheses: +(-30x^2x/(3(x+1)*2(x+1)*6(x+2))), so:

-30x^2x/(3(x+1)*2(x+1)*6(x+2))

We multiply all the terms by the denominator


-30x^2x

Back to the equation:

+(-30x^2x)



We calculate terms in parentheses: +(12x^2x/(3(x+1)*2(x+1)*6(x+2))), so:

12x^2x/(3(x+1)*2(x+1)*6(x+2))

We multiply all the terms by the denominator


12x^2x

Back to the equation:

+(12x^2x)


We get rid of parentheses

-18x^2x-30x^2x+12x^2x=0