1/3(t-6)-10=-3t+2

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Solution for 1/3(t-6)-10=-3t+2 equation: 



1/3(t-6)-10=-3t+2

We move all terms to the left:

1/3(t-6)-10-(-3t+2)=0



Domain of the equation: 3(t-6)!=0

t∈R



We get rid of parentheses

1/3(t-6)+3t-2-10=0

We multiply all the terms by the denominator


3t*3(t-6)-2*3(t-6)-10*3(t-6)+1=0

Wy multiply elements

9t^2(t-6t(t-30t(t+1=0

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